Convert 3D trajectories (x,y,z) to 2D(x,y) along its direction

[prosto_w_bemben]

Hello,

I've got many trajectories which consists of particles with their XYZ positions like on the picture below:

 Now, I would like to convert each trajectory to 2D (X,Y) along its direction and have got it as I called "flat". Each trajectory is in another direction so is there a chance do convert it like this: first trajectory converted along itself, second trajectory converted along itself e.t.c. Is there a chance to make it in LabView? Please, help me

[ToeCutter]

This is really a maths question rather than a LabVIEW question specifically. Why not google something like 'projection of vector on plane?'

[prosto_w_bemben]

Thanks for answer.

I'm not good in this issue and sometimes I don't know even how to find it in google. I also thought that problem could be solved in LabView.

[ToeCutter]

Well you never know- someone may yet come along with the answer. I don't know of any 'out of the box' function that does it- if you are using any extra modules they are worth mentioning as they may contain something.

[ToeCutter]

Actually i went and over-complicated it.

ground range=(x^2+y^2)^0.5

plot z vs ground range.

Simples...

[ToeCutter]

Oh, they don't all start at the origin, so it's:

ground range=((x-x0)^2+(y-y0)^2)^0.5

where x0, y0 are the coordinates of the first point.

[RavensFan]

Why a new message thread?

You already asked about this here  http://forums.ni.com/t5/LabVIEW/Angle-measurments-from-XYZ-positions/m-p/3186309#M922485

and even marked one of the messages as the solution.

Please keep discussions in one thread.

[Bob_Schor]

In my Solution to your previous post, I believe I showed you how do get the projection onto the X-Z plane.  I tried to do this in such a way that you'd be able to generalize this to a projection onto the X-Y or Y-Z plane, if you needed.  Go back and read what I wrote, and just substitute X-Y for X-Z.  If you have to do an Origin Offset, it also works the same way.

Bob Schor

[prosto_w_bemben]

@ToeCutter

I know that You took this equation as a distance between two points on 2D plane but it looks so simple when we plot this with Z cooordinate. We don't know how to check if it's rght.

[ToeCutter]

It's so simple, I can't see there's room for error- plus if it's wrong it will get torn down by another poster.

Simple tests:

Create your own trajectory in the x-z plane. Transform, compare graph with range-z - they should be identical.

Create one in y-z. Same game.

To echo a previous post- please don't create multiple threads on the same subject as it wastes time for us, and we do this for free.