Does labVIEW have a function to solve the following math problem?

[chuck72352]

In Labview what is the easiest way to solve the following problem?

|----             ---|  -1       |--     ---|                |--       --|

|  1   1   0       |            |   a     |                |    x     |

|  1   0   1       |            |   b     |     =         |    y     |

|  0   1   1       |            |   c     |                |    z     |

|__             __|            |_       _|                |_       _|

from the equations:

     a = x + y

     b = x + z

     c = y + z         where a, b, c are know values.    The problem I actually have is a system of 9 equations.

Thank you.

[CMal]

LabVIEW includes a variety of linear algebra VIs that are useful for problems like this.  Take a look at the Solve Linear Equations VI.

Chris M

[chuck72352]

I dont really see how I can apply the VI that you suggested to solve my problem.

[CMal]

You have a known matrix, a known vector, and a vector you need to solve for given the equation Ax = b.  This is exactly the problem this VI is designed to solve:

With the values I made up for a, b, and c, the solution is [2, 3, 4].

Chris M

[chuck72352]

The values of the matrix are not known, so I'm trying to use an inverse square determinant to solve the problem.

[CMal]

I think you'll need to better clarify exactly what you are trying to solve.  Your original post suggests that the values of x, y, and z are the only unknowns.  If you're given a set of equations like (a=x+y, b=x+z, c=y+z) then that is indeed the case, and the solution I mentioned will work.  If that's not the case, then please be as detailed as possible in describing the actual problem you're working on.

Chris M

[chuck72352]

In my application I'm trying to find inductance values in a circuit. Basically the circuit is a three phase motor and I can only measure the paths between sets of coils. to calculate the individual component values. So I dont have coefficients to enter in the top matrix as you've shown. That's why I was trying to use a square determinant.

[RavensFan]

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@chuck72352 wrote:

 So I dont have coefficients to enter in the top matrix as you've shown.

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But those are the coefficients you provided in your example!  So if you don't have them, how were you able to provide them?