Hi all,
In Intel's OpenCV Image Processing Library (which is entirely written in C/C++), there is a C typedef struct IplImage which is defined as (in condensed form):
typedef struct _IplImage
{
int nSize; /* sizeof(IplImage) */
int ID; /* version (=0)*/
int nChannels; /* Most of OpenCV functions support 1,2,3 or 4 channels */
int alphaChannel; /* ignored by OpenCV */
int depth; /* pixel depth in bits: IPL_DEPTH_8U, IPL_DEPTH_8S, IPL_DEPTH_16U,
IPL_DEPTH_16S, IPL_DEPTH_32S, IPL_DEPTH_32F and IPL_DEPTH_64F are supported */
char colorModel[4]; /* ignored by OpenCV */
char channelSeq[4]; /* ditto */
int dataOrder; /* 0 - interleaved color channels, 1 - separate color channels.
cvCreateImage can only create interleaved images */
int origin; /* 0 - top-left origin,
1 - bottom-left origin (Windows bitmaps style) */
int align; /* Alignment of image rows (4 or 8).
OpenCV ignores it and uses widthStep instead */
int width; /* image width in pixels */
int height; /* image height in pixels */
}
IplImage;
There is also a struct cvSize that is defined as:
typedef struct CvSize
{
int width; /* width of the rectangle */
int height; /* height of the rectangle */
}
CvSize;
/* the constructor function */
inline CvSize cvSize( int width, int height );
Now, I used one of OpenCV functions to load an IplImage (ie IplImage *image) and returns a pointer to it. It successfully loads and returns a long integer pointer.
One of the functions in OpenCV requires the parameter to be the following (written in C):
cvSize(image -> width, image -> height)
How would you represent cvSize(image -> width, image -> height) within LabVIEW? I will need to go to the pointer and extract the width and height information from the pointer.
