11-19-2014 05:09 AM
I have a problem i can't put into words (maybe there is already a topic, but i can't find it) so, see the attached image.
Solved! Go to Solution.
11-19-2014 05:24 AM
Adding an image is good but that either explains the problem. Please explain with that image what is the problem you are facing.
11-19-2014 05:25 AM
Image looks good
so what are we all suppose to do with it?
11-19-2014 05:34 AM
I want to move (in this case) the first 3 elements behind the last elements, the index becomes bigger, that is important, because I want to take an average form the index with an 1 as element.
11-19-2014 05:42 AM
Check out the Rotate Array function.
/Y
11-19-2014 05:47 AM - edited 11-19-2014 05:48 AM
Hi henk,
I want to move (in this case) the first 3 elements behind the last elements, the index becomes bigger, that is important
- get a subset array from your first 3 elements
- append it to your existing array with BuildArray
- replace the first 3 elements by zeros
That is what you should do based on your image and explanation…
@Yamaeda: RotateArray doesn't increase array size. You might rotate and prepend 3 addtitional zeros in front…
11-19-2014 05:53 AM
11-19-2014 06:25 AM - edited 11-19-2014 06:29 AM
Do I have to use the concatenate function in builarray?,
11-19-2014 06:26 AM
11-19-2014 06:29 AM
and how do you replace 40 ones into zeros?