How do I convert 16 bit Binary to ASCII text

[altenbach]

Hmm, so what needs to be done???

So far we know how the data is represented. What kind of input do you have and what kind of output do you want?

(Better just give us an example VI with typical data as default in a control of the desired type and a description on how the output should look like).

[DSMarcinko]

Output is a +/- DBL value.

Input are two hex decimal words.

The two words need to be converted to binary (10010......) and concatenated to form a 32 bit binary number. If the first bit is a one, the bits must be flipped add a one etc. prior to performing the 2's complmentary math to arrive at a number that is then negated. If the first bit is zero, easy, just use the remaining 15 bits to perform the 2's comp math. Hope this helps

Thanks

[altenbach]

Can't you just typecast it into a I32, then convert to DBL and scale to +/- 0.5?

[DSMarcinko]

I don't know?

What would your solution be for

word 1 = 624

word 2 = 2448

Max/Min Value +/- 1.0240E+03

resolution 3.8147E-06

MSB = 2^12

LSB = 2^-18

Full scale of the data 8.1920E+03

[altenbach]

Your problem is way overdetermined, the only thing you need is log2(MSB) (-18 in this case), which gives the resolution.

(I don't know why you need the "min/max" and "full scale" and all that. Do you need some additional scaling?)

Anyway, the attached (LabVIEW 7.1) is one possibility. You should really check it with some inputs that yield a negative number, though.

My result for your sample inputs (624,2448) is about 156.

Message Edited by altenbach on 06-21-2006 02:02 PM

[altenbach]

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@altenbach wrote:

... log2(MSB) (-18 in this case)...

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Log2(LSB) of course. Sorry for the typo. 😉

[DSMarcinko]

altenbach,

You VI is simple and works with negative numbers. More importantly, your VI provides verification for my VI.

Thank you

Where can I send your 2 - JDAM product patches?

[altenbach]

Jdam,

My services here are freely volunteered. 😄 I am glad to help!

(Of course stars are always appreciated, so don't forget to rate my contributions if you have not done so already ;))

(Somehow, I doubt that I have any personal use of any jdam products in the near future. 🐵

[DSMarcinko]

Altenbach - You are five stars in my book.

I came accross a new problem that I was wondering if you could assist to simplify?

Same type data 16 bit word

Field name    Bit No   Description

Integer             -00- S     Sign Bit

                        -01- N     MSB

                        -02- ..... -10- N

                        -11- N   LSB

Exponent         -12- E   MSB

                         -13-....-14-

                         -15- E   LSB

Integer    Resolution 1    MSB 2^10    LSB 2^0

Exponent  Resolution 1  MSB 2^3      LSB 2^0

Is there a simple way of handling this problem?  

[altenbach]

Since the LSB of the mantissa is 1 and the exponent is always positive, the result is always an integer and will fit into an I32.

I also assume that the exponent is meant to be base 2, i.e. the desired result is (mantissa x 2^exponent). If the definition is different, modify accordingly.

Here is a simple possibility to convert to I32 according to the given rules, see if it gives the right answer for you. Sorry, I cannot test this. No guarantee that its right. 😉

Message Edited by altenbach on 06-22-2006 03:52 PM