LabVIEW
How does memory allocation works in shared clone reentrancy?
Hey. I'm building a VI that uses recursion to calculate Fibonacci series. I set-up the execution type of VI to shared clone reentrant. While running the VI, I'm getting a compilation error which says "You must have a VI that uses shared reentrancy or dynamic dispatching in any recursive cycle. For recursive calls to work, all VIs in the cycle should be reentrant and at least one must use dynamic dispatching or shared reentrancy.". I found a variety of solutions to this problem namely changing the call setup to either reload with caller or load and retain on first call, enclosing the content of my VI inside a structure, using in place element structure, etc. But my question is why the error occurred. I've attached the VI for reference. In the attached VI, in True case, if the wire to the indicatior is wired to the tunnel to which the control "Curr" is connected to, this works. But not when it is connected to "Prev" control. Why this happens? Thanks in advance.
@Martin_Henz wrote:
Funnily enough, it works when a completely pointless numerical display is added.
Interesting. I've had something happening a few years ago where the optimization was too aggressive and removed stuff i was actively probing. I wonder if this is something similar.
To find Fibonacci numbers, it is simpler (and probably much more efficient!) to just have one flat diagram, though.
(I learned LabVIEW way before recursion was even allowed or shared clone available and won't comment 😄 )
If you really want a recursive solution, have a look here.
