LabVIEW
Identifying 2nd and 3rd Loop in a Graph
Solved!
Then it's time to use "Array Max & Min Function" again 
Look at my suggestion:
This sets the X- axis range to a range which is [expand range] higher than the distance of the 2nd and 3rd peak.
OK, got it. Use "Array Subset" from the array palette to extract the interesting part of the array. Then you have to adapt the cursors
Here's a few more thoughts which might help:
1) The reason the X scales aren't correct are that the graphs are not showing the correct offset and multiplier. You can do something like this to make them show correctly (this is equivalent to creating an X array as in your original VI, but much simpler!).
2) To compute the distance marked X, then I think the easiest is to subtract a Median Filtered waveform from the data like this:
3) The computation of the peak locations using the peak detector looks like a good approach, but I'm not sure if your calculation of W is correct - the code is finding a FWHM of the maximum value, but that conflicts with your original figure which shows W as the width of the first peak - which should lie inside the second and third peaks. You might need to be more specific about what the value is that you want to calculate, but one option might be to look for the points of maximum derivative either side of the first peak, and take the width between those. This gives a W=0.322 shown by the green lines on the graph below.
