Integration Express vi returning dt<=0 error

[rwbrook@integratedps.com]

I am not trying to do anything too difficult here.  I have a 30 Hz sine wave.  10,000 Hz sampling rate, 32500 points.  I can see the waveform, no problem.  I first pass it through the scaled EU vi.  When I put it through the integration express vi I get the dt<=0 error.  There isn't anywhere to tell it the dt, other than the incoming time waveform, which appears to be fine.  What am I missing?

[rwbrook@integratedps.com]

Here is the code that is giving me the problem.  I have also included the time waveform I am feeding the eu and a_v_d vi's.

[Patrick_NI]

Hello rwbrook, 

I tried simulating your process but could not replicate the error.  Would you mind posting a screenshot of the error message?

Thanks!

[rwbrook@integratedps.com]

thanks for the feedback.  I was able to get it working!  Now, the only problem I have is calculating the RMS overall from the integrated time waveform.  With 32500 points, the ringing is settled out after approx. 1 second.  That leaves 2.25 seconds of unadulterated time data to work with.  What I need to do is cut off the first 1 second of time data.  I will also chop the 32500 points of the tach signal as well so that the phase will work.  I have found a vi for zeroing out data at the end of the time block, but not the beginning.  Any ideas for getting that accomplished?

[Joshua-B]

Hi rwbrook,

If you need to work with only a portion of a dynamic data signal, you may want to use the Extract Portion of Signal Express VI.  

[Joshua-B]

Hi rwbrook,

If you need to work with only a portion of a dynamic data signal, you may want to use the Extract Portion of Signal Express VI.  

[rwbrook@integratedps.com]

Josh,

Thanks!  That sounds like it will work.  As soon as my IT department fixes my laptop, I'll give it a try.

Ron