Hi Thijs
You could test each number in the array with the "Not a
Number/Path/Refnum?" function in the comparison palette. Then, if you
find a NaN value, if you stored the previous value in a shift register,
keep that value. Check for any subsequent NaN's (and count how many)
until you find another non-NaN, and then do your maths to fill in the
appropriate array values (carry the array on another shift register).
Paul
Thijs Boeree wrote:
> Hi,
> I have an 1D array of numbers but there are also NaN's in it, does
> anyone knows how to remove them and fill em in with interpolated
> numbers:
>
> So i have for example this:
>
> 5.67
> NaN
> 3.46
> 2.56
> 4.68
> NaN
> NaN
> 3.21
> 1.04
>
> And i want it to be this:
>
> 5.67
> 4.56
> 3.45
> 2.56
> 4.68
> 4.19
> 3.70
>
3.21
> 1.04
>
> It a linear interpolation, If there is one NaN space: first value +
> third value / 2 fill in.
> Where the two NaN's are i do the following: (4.68 - 3.21)/ 3 = 0.49 ->
> 4.68 - 0.49 = 4.19 (first filled up NaN value) then 4.19 - 0.49 = 3.70
> (second filled up NaN value) but now in LabView?!
>
> Anyone?!
>
> Best regards Thijs
--
Research Assistant
School of Physiotherapy, Curtin University of Technology
Selby Street, Shenton Park, Western Australia, Australia. 6008
email: P.C.Davey@curtin.edu.au
Tel. +61 8 9266 4657 Fax. +61 8 9266 3699
"Everyone who calls on the name of the Lord will be saved." Romans 10:12
"For all have sinned and fall short of the glory of God, and are
justified freely by his grace through the redemption that came by Christ
Jesus." Romans 3:23-4
