LabVIEW
Passing array to shift register causes input tunnel to be output tunnel
I am trying to update an array in one of 3 cases in a case structure. I pass it out of the case after building array, as a shift register. I dont want to do anything to the array in the other two cases. So I pass the array as is from the input to the output (standard procedure). But here I get an error that "You have connected an output loop tunnel to an output loop tunnel. "
Shift registers seem to work with arrays for other people so what am I doing wrong? The data comes from certain instrument drivers (will link them later)
You are going to need to post the actual VI here. I suspect you have a miswire, possibly including a tunnel that is hidden underneath something.
Most people here are not using the latest version of LabVIEW, so I recommend doing a File->Save For Previous to save your VI in 2019 or older to get the best chance of somebody being able to help.
Hi mastibaaz,
@mastibaaz wrote:
I am trying to update an array in one of 3 cases in a case structure.
Beside your original problem:
Why do you need to insert two scalar values into an empty array?
When you want to build an array you should use the BuildArray function!!!
