Scan String Problem

[jyang72211]

I got an error when I run the attached code.  When I get rid o the comma after the last %s, the error would be gone though.  What's going on?

yik

[tbob]

%s matches a string up to the next space, I believe.  Since a comma is a valid character, %s is matching "C,".  If you specify %1S then you can keep the comma because it will match only 1 character, and the comma will not be part of the match.

Wow, I'm actually learning this regular expression nightmare.

[Darin.K]

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@tbob wrote:

Wow, I'm actually learning this regular expression nightmare.

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This is actually a format string, which to most people is just a bad dream.

If you do not know the length of the LocCT string you could replace '%s,' or '$1s,' with '%[^,],' which will give you a string with all characters except a comma followed by a comma.