Updating tables value

[michele.santucci]

I'm having troubles updating a two columns table:

step table control is passed to this VI and updated within the for loop.

If I step trought the loop I can see values updated but as long as the loop terminate the resulting values are un-modified.

I'm missing something?

Best regards,

 Mike

[GerdW]

Hi Michele,

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@michele.santucci wrote:

If I step trought the loop I can see values updated but as long as the loop terminate the resulting values are un-modified.

I'm missing something?

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I guess you miss to "THINK DATAFLOW!"…

As long as the FOR loop iterates the data of the "step table" array is kept in the shift register. Once the loop finishes the control gets new data by writing them into the local variable.

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@michele.santucci wrote:

I'm having troubles updating a two columns table:

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What is your "trouble"?

[michele.santucci]

I need to update the values of the control with the data updated within the for-loop.

Probably I have not understood how for loop and shift registers works but I just took a working code and changed the type of the input field.

[GerdW]

Hi Michele,

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@michele.santucci wrote:

I need to update the values of the control with the data updated within the for-loop.

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So you need to "THINK DATAFLOW!" again!

Where do you need to place this local variable when you want to update the control WITHIN THE LOOP???

[michele.santucci]

Given your suggestion I think I will have to move the table update inside the loop.
Anyway.. what I'm doing is trying to generalize a piece of code I inherited, this:

That was working...

[pincpanter · Accepted solution]

I guess you want to update the table in the calling vi?

Then you need to pass it by reference - as in the example code - not by value.  If you pass only the value to the subvi, the original control will remain unchanged.

Alternatively, you may pass the new value back to the calling vi (via an indicator) and update the table.

[michele.santucci]

I got this..