Which is the best way to create an array of waveforms?

[sqrt(-1)]

Hi all.

Usually, the best way to create an array is to use Initalize Array and replace elements using a while loop and a shift register, as reported here:

But... if I want to create an array of waveforms? I think that it should not the better method (from the point of view of performance).

A waveform contains several elements, in particular it contains an array of double (Y array).

So, what happen if I apply the code above with waveform (see the following figure)?

The Initialize Array function allocates a certain amount of memory for my array. The waveform used to initalize the array contains a empty array of data (Y array is empty). When the i-element is replaced in the array, the Y array is not empty and LabVIEW should allocate new memory for it. Am I right?

If my argument is correct, in this case does the auto-indexing with a for loop should be preferred rather than the previous method?

Thanks

[hmarcano]

Have you tried to keep it simple,

Am not an expert on memory allocations but the posted example may be worth of consideration for simplicity's sake.

[Hooovahh]

I think in this case OP is talking about replacing some elements in the array, so pre-allocating that to the maximum array size then doing a replace is the most efficient.  The example is probably simplified.

That being said OP can try something like this, which will preallocate 100 waveforms with 1000 points in each.