04-26-2012 09:52 AM
Hello,
I am using the development vision,
I've got a table and in the fourth column of this table, there are some addresses that I need to open separate them individually.
How could I get these addresses on separate strings and transform each of these addresses "string" to "Path"
Thank you.
04-26-2012 09:57 AM
There is an String to Path function.
04-26-2012 10:03 AM
Ok,
but I want to separate the lines of the colum in different strings, ofr after i convert String to Path.
EX:
address
aaa
bbb
ccc
ddd
Address Address Address Address Address Address
aaaa bbbb ccc ddd eee fff
But Thanks so much....
04-26-2012 11:11 AM
Get the string from the last column and use Spreadsheet String To Array Function with a delimiter of carriage return/linefeed
04-26-2012 11:29 AM
i'm sorry, but i don't know how can i get the string of the last column.
Check the attachments with example.
And said for me how can i get the last column string, please.
04-26-2012 11:44 AM
I can't open the VI since I only have LabVIEW 8.6.
04-26-2012 11:53 AM
I´'m sorry..
See now the attachments.
04-26-2012 12:56 PM
Use the Index Array function to get just the column that you want. This will give you a 1-D array of the text in that column.