c programe to labview code

[sumeshkp03]

Hello,

I am a beginner in labview. Can anyone please help me to convert the C programe code to labview code??

#include<stdio.h>
int main()
{
	int array[]={1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8,1,1,1,1,1,1,1,1,1,1,1,20,0,40,50,1,1,1,1,1,1,1,1,1,1,5,6,7,8,1,2,3,4};
	int n = sizeof(array)/sizeof(array[0]);
	printf("size of array is :%d \n", n);
	int i;
	for(i=0;i<n;i++)
	{
		int j=0;
		int count=0;
		if(array[i]==1)
			{ 
			    j=i;
				count=1;
				while(array[j]==1)
				{
					j++;
				    count++;
				}
				if (count==10)
					printf("your  data is at  %d location in array \n",i+count);
			}
}
	return 0;
}
		
Basically the code is finding a small sequence of data ,say 10 numbers from a large array of data, say 10000 numbers.

[tyk007 · Accepted solution]

I assume you have looked over this: http://www.ni.com/academic/students/learn-labview/

Give it a go and post what you have completed so far so that we can give you specific pointers.

[GerdW · Accepted solution]

Hi sumesh,

Basically the code is finding a small sequence of data ,say 10 numbers from a large array of data, say 10000 numbers.

That's what that code does…

- You need a loop to run over your input array.

- You could use ArraySubset to read a subset of required length.

- You can compare this subset with your predefined pattern you are looking for.

- When both are the very same you can output this "pattern at location %d" message

That's a nice job to learn LabVIEW and some of it's very basic features! (Like autoindexing vs. non-indexing loop tunnels, comparison modes of compare functions, array handling and array functions…)

Show what you have tried and explain where you have failed!

(We will not do your homework!)

[crossrulz · Accepted solution]

Just to add to the confusion, we goes use Flatten To String on both the data and the search criteria and then use Search/Split String to do the search for us...