08-29-2005 11:36 AM
08-29-2005 11:49 AM - edited 08-29-2005 11:49 AM
You want to use a FOR loop that has a constant wired to the "N" node equal to the number of values in the vector. Create a second constant outside the loop that has the value for "a" in it.
Now inside the loop, multiply the "i" node time 0.01, and add the result to the value coming from the "a" constant. Wire the output of the addition out through the wall of the loop, connect it to an array indicator and you're done...
The first time through the loop, i = 0 so you will calculate: a + (0.01 * 0) or a; the second time through the loop it will calculate a + (0.01 * 1) or
a + 0.01; and so on.
Mike...
Message Edited by mikeporter on 08-29-2005 12:50 PM