how to present each case in a case structure a certain percentage of the iterations

[altenbach]

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@jcarmody wrote:

Maybe the probability of a "1" is valid for each element, but I don't think this is what the OP wanted.  This example should have five Trues, no?  I couldn't get it to fill it with 15 Trues, but 14 happened pretty quickly.

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What point are you trying to make? If you have a 0.25 probability for each element, a sum above 14 is very unlikely (but with a probability that can be calculated exactly).

It really depends what the OP wanted. If you know that there are exactly 5 trues every time, you can often predict the outcome early. For example if the first 15 elements are false, you can predict the outcome of the next five with 100% certainty. Same if all five TRUEs show up early. Only the Bernoulli solution gives you unpredictability up to the last pick.

[jcarmody]

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@altenbach wrote:

What point are you trying to make?

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My point was that Bernoulli Noise.vi doesn't do what was asked.  If I change my "ones probability" constant to 0.1, I get three Trues more often than I get two.  The OP wrote "I want to present the test stimulus on 90% of the trials and the catch stimulus on 10%".  OP didn't say that he wanted a 90% probability of a test stimulus being presented at each trial.

[altenbach]

As I said, this makes the test flawed if the subject is good at "card counting". Just trying to help. 🙂

[jcarmody]

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@altenbach wrote:
[...] Just trying to help. 🙂

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You did, thank you, but I missed your point the first time.  I understand now...