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problem when I create a library automatically using a vi.

I create a library which contains a Shared Variable by the vi as the attachment shows, but the property of the autocreated Shared variable is not same with which I set in the vi, mainly in the propertys of Network.AccessType and Alarming.BadStatus.Enabled. But other propertys are same with which I set, What's wrong with this Vi?
 
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LabVIEW 8.20程序设计从入门到精通已经出版,敬请关注!
欢迎访问LabVIEW学习乐园: http://labviewstudy.blog.edu.cn
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refresh
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LabVIEW 8.20程序设计从入门到精通已经出版,敬请关注!
欢迎访问LabVIEW学习乐园: http://labviewstudy.blog.edu.cn
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refresh again
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LabVIEW 8.20程序设计从入门到精通已经出版,敬请关注!
欢迎访问LabVIEW学习乐园: http://labviewstudy.blog.edu.cn
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New problem: the created libarary cannot be deployed with the error: MyLibrary\My Variable deployment failed (error: -1967362041).

After you dobleclick every shared varaible and click ok(without any change), then the libarary can be deployed successful!

It's very strange to me, can anyone explain this?

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LabVIEW 8.20程序设计从入门到精通已经出版,敬请关注!
欢迎访问LabVIEW学习乐园: http://labviewstudy.blog.edu.cn
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unluckly, no one reply meSmiley Sad
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LabVIEW 8.20程序设计从入门到精通已经出版,敬请关注!
欢迎访问LabVIEW学习乐园: http://labviewstudy.blog.edu.cn
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