09-24-2008 04:58 AM - edited 09-24-2008 05:01 AM
Hallo all,
i would like to find the fourier transform of the function: V(x,y,t) = V = 1/(4*((pi)*t)**3/2) * exp(-(x**2+y**2)/4*t) . This equation describes the temprature propagation through a block of metal . For example, at the surface of the block (x=0, y=0) the function should have a sharp peak and the corresponding FFT of this point should look like a lowpass filter.
i made a small program, which shows the FFT of this function, but i do not know how i can find the FFT for example exactly at the point (x=0,y=0) or any other point that i am interested in? i mean, how can i insert the values of x,y that i am interested in, to be shown in the FFT?
thanks.
11-04-2008 05:39 AM
Hi Oliver
Having looked at the code attached, it seems that all you need to do in order to find the FFT at a specific point is to remove the random number generator from the x and y inputs to the formula node and replace them with either a constant or a control, so that you can specify the values of x and y. I hope this helps, but please let me know if you have any other questions.
Regards
Jeremy