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06-15-2009 12:27 PM
Hi everyone,
I'm a new member of this forum, I have been trying to figure it out how to build a pulse oximeter using the correct theory. I've got a emitting drive circuit to switch both leds at two different times but I'm not obtaining the right signal from the output of a transimpedance circuit. Not sure if I'm using the right swtching times (60us ON in a period of 1.2ms) or if I'm not measuring the right output of the circuit.
I'm a bit confused about how those times work, the whole circuit has several phases it starts with a emitting drive circuit which turns on and off each led, after that there is transimpedance circuit which captures the recieved light and transforms it into a voltage value, immediately after there is aBPF(Band Pass Filter) that has cut off frecuencies of (0.5-20)Hz which eliminates the DC level filters the noise signals from ambient light. Am I not supposed to get the PPG signal at this point?
Can somebody help me please??
Thanks
06-15-2009 02:19 PM
Japex,
It is generally better to start a new thread rather than responding to an old one. Especially since your question is about a similar topic, but considerably different in detail.
If you are switching the LED 0.06 ms ON and 1.14 ms OFF, then filtering the detector output with a 20 Hz band pass filter, I doubt that anything gets through the filter. You are looking for a 5% duty cycle signal pulsed at 833 Hz after it passes through a 20 Hz filter. The filter completely eliminates your signal.
What you need to do is to use something comparable to a sample and hold circuit or synchronous detection circuit between the photodetector/amplifier and the BPF. This will reconstruct the pulse signal which can then be filtered.
Lynn