02-20-2019 08:19 AM - edited 02-20-2019 08:40 AM
Hello, I just started to work in LabView2012 and I need some help.
I have a web-camera, which catches the reflected laser signal. It’s necessary to receive a gaussian intensity distribution graph. It means I have to find the center of the obtained circle and estimate how the intensity subsides from the center along the radius.
Example in the pictuare.
I will be grateful for any help.
02-20-2019 08:45 AM - edited 02-20-2019 08:48 AM
Dear Masha (and Здравствуйте),
when posting in an English forum you should also post in English. (My Russian is a little bit rusty, but I think I got your question.)
Edit: Thanks, you edited your post while I was writing mine…)
- Instead of analysing videos you should start with analysing still images.
- Did you try to search this LabVIEW board? I'm sure there are other threads about image analysis!
- There are also examples for finding center/circumferences of circles…
02-20-2019 06:06 PM - edited 02-20-2019 06:08 PM
A 2D gaussian distribution is NOT a circle, but once you fit your 2D data to a 2D Gaussian, you can determine the width (SD, FWHH, or whatever), giving you the center and size of that circle at the desired threshold.
What is the datatype of the image? If it is just grayscale, you can fit the data directly. If it is RGB, get the R component first if it is a red laser. Is the detector linear with intensity?
Now you can fit it to a symmetric 2D Gaussian, e.g. as described here.