while loop in for loop

[BluE12]

hello,

i have a problem with the following:

it starts and doesnt end. only the first "m" and "b" gets inside the while loop. afer "=" there is false. Why is this while loop standing still?

[dkfire]

How do you know it is standing still ?

What if it can't find a true, how do you stop it ?

[_Bryan]

The stop condition is that your number has to equal zero.  You did not get a zero so the loop does not stop.  You could try less than or equal to zero for a stop condition.  Put a probe on the number feeding into your condition.

[BluE12]

ok, that could be the reason.

Good idea with the less than or equal to zero for the stop condition.

But this would only function, if the line-value begins with a value/values less than the values of the comparing array.

So i have to set a case structure for this i think.

[dkfire]

You could also make it without a while loop:

[Mark_Yedinak]

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@dkfire wrote:

You could also make it without a while loop:

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One thing to note about the above code. If the input arrays are not the same size the loop will only run a number of times equal to the length of the shortest array. If an empty array was input the loop would not run.

[_Bryan]

You can also use the in range (on the comparison palette) and define the upper and lower limits of when you want it to stop.

[BluE12]

this code looks nice. instead of searching for the 0 i could square the values in the array and search for Min.

I will try this tomorrow. I think there are some other mistakes in my vi on top, because "array with x values" and "array with indizes" (the lower lines) are on 0 when the program runs and nothing varies. But the first point has the coordinates y=0, x=90.

edit: the arrays have the same length.