why this vi is not working?

[BryanL]

I need to select out the strings that do not contain the character "." in a string array. The attached string should work but didn't. Would someone point out why? Thanks.

[LV_Pro]

try this one

P.M.

[BryanL]

Thanks PM, but I am using LabView 6.1, could you post your vi in that version? Thanks.

[LV_Pro]

Unfortunately, no as I only have 7.1 installed, so the best I can do is 7.0. I will do that in the hopes that someone will kindly do the conversion from there to 6.1

[BryanL]

Thanks PM. I shall be able to look at LV7.0 in another computer system later.

[LV_Pro]

It's late, lost work finding out that someone plugged in my computer to the wrong outlet on the UPS (Doh!) Here, the change is trivial, in fact I left your original in just not connected.


P.M.

big forehead slap!!!

[altenbach]

"." has a special meaning in a regular expression. Use "\." instead to cancel the special meaning
(Simply ad a backslash before your period). Try it! 🙂

Check the online help for details on regular expressions. (right-click on "Match Pattern"...help").

Message Edited by altenbach on 06-08-2005 03:02 PM

[Joe_H]

here it is in 6.1

[BryanL]

Thank you all for the quick help. Both vi works great!

[altenbach]

Here's a slighly cleaned up version (LabVIEW 6.1). Notice that you can eliminate a lot of unecessary fluff.

Wire the offset output directly to the case structure.

Use built array instead of "Insert into array", it is much cleaner.

etc.