On Tue, 6 Aug 2002 22:47:37 -0500 (CDT), Bruce Ammons
wrote:
>Richard,
>
>By your definition, it would be the LSB format. The higher bits are
>always zero. The values remain the same. It is just like converting
>a U8 to I16. Note that 16 bit images are signed (I16) not unsigned
>(U16).
Thank you.
---
regards,
Richard Rudek.
MicroDek, Sydney, Australia.