I want to invoke cmd.exe by using call executable step.
I did the following.
- Pulled call executable from step to main sequence window
- In File path name, gave cmd.exe and path as C:\windows\system32\cmd.exe
- In Working Directory, selected "Use Current Working directory"
- In Initial Window State, selected "Show Normally Activated"
- In Argument Expression, I used "COPY source.dll destination.dll"
I saved and then executed the sequence file. I get an Run-time error.
Could not find file: "
Error Code: -17208; File or directory not found.
I even changed the Argument Expression to "/C COPY source.dll destination.dll" as per recommendation in one blog. This also didn't work.
Any help on this is appreciated
