Diagram Disable Structures

[SercoSteveB]

A VI contains the following Diagram Disable Structure.  Is the VI Run Arrow broken?

NOTE:  The Enabled case of the Diagram Disable Structure is empty (contains no wiring) and the rest of the VI does NOT contain any errors..

a) YES

b) NO

[crossrulz]

TRUE FALSE, assuming the rest of the code is runnable.

Just realized I misread the question last night...

[rsmrostov]

not broken, vi runs

[#4]

b)

[A.Bernau]

b

[LordNobady]

b.

[DesasterMaster]

B

[nik35324]

NO

YES: Assuming error in the rest of the code.

[SercoSteveB]

Post modified to include a note that the rest of the VI does NOT contain any errors.

[sriveni]

B

[a.guzman_87]

B

[MrStevenUND]

B

[shargurudk]

And B. The vi wont show broken arrow

[whitecr]

Ans: B.

If we disable any node or wiring in block diagram LabVIEW compiler will not complie the code inside the disabled block diagram. So there won't be an broken arrow in this VI.

Nice question Steve. Pls post some other questions regarding LabVIEW compiler.

[ashwinilele]

B

[SercoSteveB]

Answer: B.  Nice one crossrulz, rsmrostov, DavidCorney, Andreas23, LordNobady, Dennis Amelung, nik35324, sriveni, a.guzman_87, MrStevenUND, shargurudk, whitecr & ashwinilele

whitecr LabVIEW Compiler questions coming up the week starting the Monday15th March.

[ramesh44]

i am quite confused with this question and the previous question both looks similar but answer is different can any one explain me why is it so

[crossrulz]

Take a closer look at the output tunnel.

This one has a dot in the middle to indicate that the tunnel is set to "Use Default if Unwired".  Therefore you do not have to wire anything up to that tunnel in the other case.

The other question has nothing in the middle.  So that "Use Default if Unwired" has been turned off. You therefore have to wire up every case, or for the Diagram Disabled Strucuture the enabled case.  Since it was noted that the enabled case was empty, you have a broken run arrow.