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Re: Threshold Array

SercoSteveB
Active Participant

What are the contents of Numeric Array Out following execution of the VI?

Threshold Array 30_10_2014.png

Threshold Array Answers 30_10_2014.png

Comments
robs777
Member

d

Not applicable

D)

vijayb.chaudhari179@gmail
Member

piease explain what exactly this threshold 1d array does?..SercoSteveB

crossrulz
Knight of NI

D



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crossrulz
Knight of NI

vijayb.chaudhari179@gmail.com wrote:


                       

piease explain what exactly this threshold 1d array does?


                   

Why don't you just look it up in the LabVIEW help?  Threshold 1D Array



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Unofficial Forum Rules and Guidelines
"Not that we are sufficient in ourselves to claim anything as coming from us, but our sufficiency is from God" - 2 Corinthians 3:5
nik35324
Member

D

vijayb.chaudhari179@gmail
Member

ya i understood it.

MrStevenUND
Member

D

heavypoet
Member

D

adamharriscpcc
Member

We built this in class and it comes out with 0, 1.5, 2.  Can anyone explain?

crossrulz
Knight of NI

I'd have to see your code.  That sounds like you made a wiring mistake somewhere.



There are only two ways to tell somebody thanks: Kudos and Marked Solutions
Unofficial Forum Rules and Guidelines
"Not that we are sufficient in ourselves to claim anything as coming from us, but our sufficiency is from God" - 2 Corinthians 3:5
adamharriscpcc
Member

yup, a typo, we had "11" instead of "1" but couldn't see that because the width of the array doesn't auto-resize. 

LordNobady
Member

D


Learning LabVIEW since January 2013
Jsoni
Member

D

mini09
Active Participant

D

SercoSteveB
Active Participant
ersmt444
Member

Hey Please help,

According to formula: y=y1+(x-x0)(multiply)y2-y1(divide)x2-x1

This formula is used for findout fractional index.

 

The values are taken below becuase 2.5 lies in between these values:

For index 0

x0=0;x1=;x2=2;x3=3;x4=4...

y0=1;y1=2;y3=3;y4=4;y5=5...

for index 1 and 2 will be somthing different.. 

For index 0,

where given values are as:

x1=1   y1=3

x2=2   y2=2 

y=2.5

x we will be 1.5 after solving through formula.Remaining values can be solved similarly by changing the value of index from 1 and 2 and we will get values 0.5 and 0 respectively.So the answer should be for x:

1.5

0.5

I have done many examples related to this but here my LabVIEW program give the same answer as mentioned above.How? 

ersmt444
Member

I got the point.It is something different.Here the index remained same but moving from 0 to next and thus the value of index remained same until it reaches the maximum value.