Tx const Async

[Cozy1]

In Tx const Async example of NI USRP the sampling rate of the sine wave and cosine wave is kept same as the coerced IQ rate of the USRP. In such a such a case,  during IQ modulation the bitstream of the whole sample is taken together as samples Or considered as individual bits?  If they are considered as different bits,  will it be any different had it been something similar to SSB?  As the rf signal would be expected to be coswmt*coswct - sinwmt*sinwct. This is the equation for USB SSB

[psisterhen]

The waveform is an array of complex samples, 

cos(2*pi*f_m * T_s* n) + j*sin(2*pi*f_m * T_s* n)

where f_m is that frequency of those sinusoids and T_s is the sample period.

In the FPGA, the samples of that waveform will be upsampled to the DAC rate, and converted to I and Q baseband waveforms.  These are mixed with the carrier frequency so that the RF signal is

cos(2*pi*f_m*t)cos(2*pi*f_c*t) - sin(2*pi*f_m*t)sin(2*pi*f_c*t)

as you say in your question.

So each element of that array in LV is an IQ sample.