How can I add three binary numbers and then convert to string (Hex format)?

[BryanS]

Hi All,

I have my problem "half" resolved, but need some assistance on the final piece.  Overall, I need to take three string values (hex format), convert them to binary, add them and then convert back to a string (hex format).  If that doesn't make sense maybe this will:

Final Result (My target) = 0xCC

 = 0x03 + 0x01 + 0x04

          = 0x03; 0011b

          = 0x01; 0001b

          = 0x04; 0100b

For my app, we are dropping "masking" some of the bits so that we get 1 byte:

          = 0x03; 11b

          = 0x01; 001b

          = 0x04; 100b

So...

11001100b = 0xCC

In my VI, I am taking each initial string [0x03,0x01 and 0x04] type casting them to U8.  Next I need to "mask" the binary values as shown above and then add them.  I am not sure how to do this in LV??

Thanks for the help,

Bryan

[GerdW]

Hi Bryan,

there's a conversion palette in the string palette, ever looked at those functions?

The rest is pure simple math:

It's the straight-forward way, there are other possibilities too!