How can I convert a 680x480x2 array of values into binary and then joining adjacent elements to make a 640x480 array?

[GerdW]

Hi cowboy,

"essentially I want a 640 x  480 array with each cell containing 16-bit value. The original array is double the size, with 8-bit."

Pick the corresponding bytes in correct order (as mentioned by Altenbach) and join them!

[johnsold]

Would this do what you want?  You might need to change representation or order of pages to get the right values.

Lynn

[altenbach]

That would be correct for a 3D 680x480x2 array, but I don't think this is customary for 10 bit data. More likely is flat arrangement in memory, such as in a 1360x480 array for example, with the bytes to be merged adjancent to each other.

Assuming big endian, the following might work.

 

Modify as needed. There are probably bugs....

[cowboys99]

Thank you all so much for your feedback.

Here is some additional information I have obtained about the situation:

The camera provides 8-bit data in an array on labview. Ultimately I would like to aquire 10-bit data by converting the 8-bit data into 16-bit. In binary, the last six digits would be 000000 and to my understanding, those zeros can be "cut off" to enable a 10-bit solution.

[nathand]

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cowboys99 wrote:

The camera provides 8-bit data in an array on labview. Ultimately I would like to aquire 10-bit data by converting the 8-bit data into 16-bit. In binary, the last six digits would be 000000 and to my understanding, those zeros can be "cut off" to enable a 10-bit solution.

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I'm sorry, but this still isn't making much sense.  Why do you want 10-bit data?  How does "converting the 8-bit data into 16-bit" give you 10 bits?  Also, you're going to end up storing your 10-bit data in 16-bit values anyway (the computer can naturally address 16-bit values, but cannot do so for 10-bit values), so losing the lower 6 bits won't gain you anything in terms of memory use unless you're willing to write a lot of code to pack and unpack 10-bit values.

[altenbach]

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cowboys99 wrote:

The camera provides 8-bit data in an array on labview. Ultimately I would like to aquire 10-bit data by converting the 8-bit data into 16-bit. In binary, the last six digits would be 000000 and to my understanding, those zeros can be "cut off" to enable a 10-bit solution.

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Obviously, words are insufficient. Why don't you attach a VI that contains a typical input array, either as default data in a control or indicator, or as a diagram constant?

You cannot cutoff individual bits from a 16 bit value, but you can ingore certain bits.