How to get full path of caller VI?

[jeremy_levy]

Labview 8.x broke my code.  I used to be able to refer to a VI by its name, and now it wants the full path.  Unfortunately, "call chain.vi" only returns the name.  Does anyone know how to refer to the vi (its full path) that calls a particular subvi, from the subvi?  It used to be the second element of the string array from "call chain.vi".

I'm using LV8.6.

Thanks,

Jeremy

[dan_u · Accepted solution]

Hi Jeremy,

I'm not sure about 8.6, but in 8.5.1 you can still use a string containing the VI name to open a reference of a VI that is in memory.

You can't use a path constant with just the VI name though.

 

Daniel

Message Edited by dan_u on 02-17-2009 08:34 AM

[mikeporter]

With 8.x you can still refer to a VI by just its name if its already in memory - which a caller obviously should be. Can you post the code that is causing the trouble? Or perhaps explain more completely what you are trying to do and what happens?

Mike...

[jeremy_levy]

Thanks--I had almost that in my pre-8 code, but there was a path to string conversion that 8+ does not like (and 8- required).  It was very useful to compare your png with my code.

Jeremy

[mikeporter]

Actually, you have always been able to wire a string to the open function like that.

Mike...