I’d like to ask a question regarding graph transformations.

[dlehdgh20]

I would like to transform the left graph into the right one.

For the x-axis, I used a calculated value. For example,
3 W80 MHz=37.5 nJ\frac{3\,\text{W}}{80\,\text{MHz}} = 37.5\,\text{nJ}80MHz3W​=37.5nJ.
Given that A=0.00785 cm2A = 0.00785\,\text{cm}^2A=0.00785cm2, I calculated
f=37.5 nJAf = \frac{37.5\,\text{nJ}}{A}f=A37.5nJ​, which results in 4.78 μJ/cm24.78\,\mu\text{J/cm}^24.78μJ/cm2.
This value was used for the x-axis using a division operation.

The problem lies with the y-axis.
Originally, I calculated reflectivity as BA\frac{B}{A}AB​ using data from the left graph.
However, to correct for the background signal, I need to apply the following expression:

What is the best way to use arrays to implement this calculation?

[andcadev]

Hello,

sorry, I'm not sure I've caught your question correctly. Do you want to figure out a way to extract A, B, 1, 2 ,3 and 4?

[altenbach]

LabVIEW can do all the math you ever need.

Your description is very hard to understand. The forum editor does not render your formulas, thus you should try to just insert pictures of the formulas  instead.

I don't understand how you can get a smooth curve covering more that four orders of magnitude in X from just four readings.

Can you attach a VI with typical data?