Hi Kelly,
Thanks for the solution. But I would like to know further about this mean. I have read through the help of this vi. It does not tell more other than just giving the mean of the a double.
When you say that this "VI takes an array of doubles"
does that mean (no pun intended).... (eg. an array with 10 elements) the vi will average the data within that array even though it is on-going process and return a mean double of the array?
I hope made it clear here.
Looking forward to your reply.
Once again, thanks.
juni