crc8

[manu23]

hello,

I use a CRC8 because I have no choice. The equipment I use is configured like this and I have programmed with the I2C protocol

Can you tell me which one CRC8 function please

[GerdW]

Hi manu,

the decision on CRC type is made by your equipment. Read it's manual...

[manu23]

Yes, but the concern is that I can not make a program to calculate with labview
The formula is:
 
    8bit-CRC: 0x07 = x8 + x2 + x + 1

Can you help me?

thank you

[crossrulz · Accepted solution]

I made plenty of conversions for you.  Look at those examples.  You should just need to change the polynomials to 0x07.

[manu23]

hello,

thank you for all of these conversions. But none give the right answer.
What do you mean by: You just need to change shoulds the polynomials to 0x07

thank you

[manu23]

Sorry, it is OK

[manu23]

my VI