10-18-2008 12:06 AM
Dear Sirs,
I have a question,we have a 4-20mA input,4-20mA out,24V power product,but my client need two 4-20ma output at the same time ,and on a broad.pls someone tell me the circuit.Thanks.
Cheers!
Candy
Solved! Go to Solution.
10-20-2008 02:11 AM
http://en.wikipedia.org/wiki/Current_mirror
10-29-2008 07:46 AM - edited 10-29-2008 07:49 AM
Hi,
With an analogue data transmitter module from TURCK you can solve your application.
Take two IM31-11-i modules from TURCK. Connect the 4-20mA output of the 1st module,
to the 2nd module, so you feed the current trough both modules. Then your original 4-20mA
is found at the output of both module 1 and 2.
Here is the TURCK Website: http://www.turck.de/en/
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http://www.industrial-automation-hands-on.com/
10-30-2008 02:22 AM
10-30-2008 08:25 PM
10-31-2008 02:25 AM - edited 10-31-2008 02:26 AM
Hi Candy,
It is almost right, I think. Why the diodes at the inputs.
When I look at the datasheet of your isolator (I only can read the figures not the characters ) the input is 50Ohm. So the input voltage (across the diode) is 0.2-1V. The 1N4007 starts to conduct at 0.6V.
11-01-2008 01:09 AM
11-01-2008 01:32 AM
11-03-2008 01:33 AM - edited 11-03-2008 01:34 AM
Hi Candy,
According to Ohm's law (at least at this side of the world ) a current of 4-20mA through a 50Ohm resistor gives a voltage of 0.2 - 1V
Please explain your value of 10-50mV
I do not understand your second question. A accuracy of 0.3-0.4% is rather good I think for transmitters.
11-03-2008 03:38 AM