What is Numeric Value Out following execution of the VI?
a) 0
b) 128
c) 256
d) 512
A. Reason: To U8 considers only the upper 8 bits
A
Naveensoliton wrote: A. Reason: To U8 considers only the upper 8 bits
Naveensoliton wrote:
It is actually the LOWER 8 bits that are used.
A.
Thanks for correcting.
The constent 512 is of U32 format, because of this Numeric value out is 0.
Agreed A
U8 capacity is 256 .
So 512 = 256+256
Next ll b 0 . Is it correct ?
It turns to be 0
Is it k?
Answer: A. Nice one Naveensoliton, crossrulz, MrStevenUND, LordNobady, sk_a, nik35324, gnshmrthy & ashwinilele.
Ans:A
0
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