HEX String Range check

[Sonti_11532]

Hi

Please find the enclosed snippet.

Here i'm checking the range of Hex string. The result of the attached snipped suppose to be false. But it is giving the true value.

Kindly explain.

Regards,

S Nagaraju

[GerdW]

Hi Sonti,

when using strings LabVIEW "tends" to alphabetically ("by dictionary order", my English isn't that good) use them for comparisons.

Your input value is between the range limits!

When you want to compare values you need to use numeric datatypes: convert your strings to numbers…

[PalanivelThiruvenkadam]

Based on what condition its should be false?

Check for the Hex String to Numeric and Find the values of Input Strings.

[Sonti_11532]

Hi PalanivelT,

If I convert the hex string to number, BFFFFFFF ==>  3221225471 (Upper limit)

                                                          81000000 ==> 2164260864 (lower limit)

                                                          810001 ==> 8454145 (Value)

For numeric data type the result will be false. But in case of hex string, how the range check is happening??

I have checked with the range between hex values 0 to F and i found the reliable result. What is the issue with this case??

Kindly explain.

Regards,

S Nagaraju

[GerdW · Accepted solution]

Hi Sonti,

how the range check is happening??

Did you read my answer?

Strings are sorted by dictionary order!

So your "810001" lists AFTER "81000000" and BEFORE "BFFFFFFF" in the dictionary…