Array Searching #2

[SercoSteveB]

What are the contents of 'Search Position Out' following execution of the VI?

The other case for the case structure used in the question is shown below:

a) A 1D Array containing {-1,-1}
b) A 1D Array containing {0,0}
c) A 1D Array containing {0,2}
d) A 1D Array containing {2,0}

[ambaum01]

c

[crossrulz]

A

Only the last iteration matters.  Therefore only the second row matters.  Is there a 3 in the second row?  Nope, so the Search 1D Array will return a -1.  So the contents of the -1 case will be the output.

[mini09]

A is the answer but expect an brief explanation for the flow of program.

[crossrulz]

Look at my comment above.  If you are still lost, tell us where you are stuck.

[Asha_Nagaraj]

Ans:- A

[Neelamma]

Asha i agree with u

according to me ANS :- A       

[SercoSteveB]

Answer: A.  Nice one crossrulz, gnshmrthy, Asha_Nagaraj & Neelamma

Same as yesterday; For loops auto-index rows and Search 1D Array returns -1 for 'not found', with the addition of a little reminder to never forget the dataflow paradigm.

[Musale]

can anyone explain me why Search 1D array giving output -1. there is 3 already in the array constant.??

[SercoSteveB]

Hi Musale and welcome to The Daily CLAD.

There is a dataflow part to this question as well as the Search 1D Array. 

On the first iteration of the loop the Search 1D Array returns 2 as it finds the '3' (at index 2) within the first (auto-indexed) row of the 2D array.  The VI does not complete and goes on to perform a second iteration.  On the second iteration, on row 2 of the 2D array, the Search Array fails to find a match and returns -1.  The -1 case of the Case Structure passes the {-1,-1} array to the output tunnel of the For Loop.

Hope this helps

Steve

[skian]

A