For Loop Iteration & Multiplication

[SercoSteveB]

What is the value of Numeric Value Out following execution of the VI?

a) 3

b) 4

c) 6

d) 24

[adambro]

I will say 3. Since a shift register isn't used, only the constant value of 1 will be fed into the loop on each iteration. Since auto-indexing is enabled on the array input, the loop will iterate three times, rather than four. The numeric output will only disply the result of the final iteration. At that point, i will equal 2 and so the output will be 1x(2+1).

[ahmelsayed]

as Indexing is Disabled, the indicator will display the last iteration to be 1*(3+1) = 4

[Mantesh]

Answer is: a) 3

[ManjuG]

It will iterates 3 times so 1*(2+1)=3, so the ANS is a) 3.

[StefanoFacchine]

Hi everyone,

I do agree with the nice explanation given by Adam_B, the correct answer is a).

[ahmelsayed]

Ok this constatnt cheated me ! it will output only 3 as only 3 iteration will be executed

[mini09]

Well friends accecpet with those who all go for 3..

@ steve: were have you been I missed a lot of CLAD questions were u busy?

[SercoSteveB]

Answer: A.  Nice one adambro, mahantesh, ManjuG, StefanoFacchinetti, Ahmed Elsayed & gnshmrthy.

Nice explanantion adambro, nothing more to say.

[ashwinilele]

Ans is 3

[ramesh44]

3

[rupesh.v]

Ans :a

because for loop always take lower value N  ...its always lazy..

[skian]

A